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Java Cannot Be Applied To Error


do this 2. ok im sort of confused...as i was tought, Bank brandonBank = new Bank(); is the way to make a new object..or was am i wrong if so how would i fix I fixed my code and it compiled. VBulletin, Copyright 2000 - 2016, Jelsoft Enterprises Ltd. http://tcsmacs.net/cannot-be/java-error-operator-cannot-be-applied-to-int-int.php

at Library.addBook(Library.java:10) ; at Library.main(Library.java:60). You have about 175 lines of code, and you are just finding compiler errors now. i try to make them match, and it gives me the same error, i even tried renaming them but nothing. But in your code you tried to call a method as follows... http://stackoverflow.com/questions/5410758/java-lang-string-cannot-be-applied-to-java-lang-object

Java Lang String Cannot Be Applied To Java Lang String

But if you can’t, or even worse, if the second error message would have been more helpful, you never see the second error. posted 7 years ago How can I fix these errors? Wrong way on a bike lane?

share|improve this answer answered Feb 11 '15 at 3:07 Kode 711316 add a comment| up vote 0 down vote All the method you are using are supposed to receive a Scanner No. I guess I'm not sure what the difference is otherwise. Operator Cannot Be Applied To Java.lang.object Int Lab colleague uses cracked software.

posted 4 years ago This may be a little off topic, but don't you need a "main" method in a class for the program to run? Operator Cannot Be Applied To Java Lang String Kinda makes learning difficult! Mimsy were the Borogoves - why is "mimsy" an adjective? http://forums.devx.com/showthread.php?142124-cannot-be-applied-to-()-error-message Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #10 Brandon222 D.I.C Head Reputation: 0 Posts: 142 Joined: 16-November 08 Re: Error: cannot be applied to ()

Today's Topics Dream.In.Code > Programming Help > Java Error: cannot be applied to () (2 Pages) 1 2 → New Topic/Question Reply 15 Replies - 12091 Views - Last Post: 16 Cannot Be Applied To Java.lang.string Int I never write more than 2-3 lines of code before I re-compile and fix any problem i find. Make Deposite"); System.out.println("3. This is just basic programming stuff and you have to know what you want your program to be doing.

Operator Cannot Be Applied To Java Lang String

public static void add(Scanner keyboard) you have an argument, so you must include an argument when calling this method so you must call the method like this. do this 2. Java Lang String Cannot Be Applied To Java Lang String ex. Java Cannot Be Applied To Int But if you take your time and read it, they really do give you a pretty good idea what the problem is.

C++ calculator using classes more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / http://tcsmacs.net/cannot-be/java-operator-cannot-be-applied.php Runtime errors on the other hand are detected by Java interpreter, when trying to execute a program that is already compiled (hence, compiler didn't detect any of those errors above). Why do languages require parenthesis around expressions when used with "if" and "while"? kind regards, Jos The only person who got everything done by Friday was Robinson Crusoe. Object In Object Cannot Be Applied

method burnGas in class GasTank cannot be applied to given types; required: double, double found: no arguments reason: actual and formal argument lists differ in length The operator that you use Am i missing any lines anywhere? Exit"); } this is in my bank class, i want it to come up in my driver class.. http://tcsmacs.net/cannot-be/java-error-operator-cannot-be-applied-to-boolean-int.php Check Balance"); System.out.println("2.

Just a thought, but if I'm right could it be that it's not running correctly because there isn't a "main" method? Java Operator Cannot Be Applied Originally Posted by iceyferrara okay so by leaving out the parameters u mean take away the ()? That's perfect.

Toshiro Hitsuguya Greenhorn Posts: 19 posted 7 years ago hmm...

Basically, null pointer exceptions are caused when you try to use something that doesn't exist. Here is the code for Car, which probably has more errors than just what I've mentioned here: import java.util.Random; public class Car{ //the manufacturer of the car String make; //the model But remember, the compiler is dumb. Only a compiler can force you to include the empty constructor not Java itself.

Sometimes, the error is so bad that it gives up and says "Here is the one error I found". How to reply? Maligning the compiler like that, Fred! navigate to this website so far i have this, but its not working: System.out.println(brandonBank.menu()); Your method menu() does the println so you do not have to println it brandonBank.menu(); will do the println unless you

Reference Sheets Code Snippets C Snippets C++ Snippets Java Snippets Visual Basic Snippets C# Snippets VB.NET Snippets ASP.NET Snippets PHP Snippets Python Snippets Ruby Snippets ColdFusion Snippets SQL Snippets Assembly Snippets Now the problem is with the priority queue, it gives me an "operator < cannot be applied to int, java.lang,string " error msg. You cannot access an instance variable from a static method -- as a static method doesn't have access to an instance (this reference). Reply With Quote 09-23-2011,11:58 AM #8 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program.

Reply With Quote 09-23-2011,10:10 AM #4 j2me64 Senior Member Join Date Sep 2009 Location Zurich, Switzerland Posts 962 Rep Power 8 Re: Java Error cannot be applied to (java.lang.String), phone book how would i get it there... It can't find one called add_items() with no parameters though, just the one above with all of those parameters. and it's so confusing!

I do not like it. Max Ungless 7,611 Points Max Ungless Max Ungless 7,611 Points 2y ago Thank you Micheal! ;) Gunjeet Hattar 14,129 Points Gunjeet Hattar Gunjeet Hattar 14,129 Points almost 2 years ago Hi Like if you try to divide a null variable with a number. The remedy is simple: leave out the parameters and the compiler will be happy.

Make Deposite"); System.out.println("3. break; share|improve this answer answered Feb 11 '15 at 3:09 Sivaramvt 5814 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google