Home > Cannot Be > Java Lang String Cannot Be Applied

Java Lang String Cannot Be Applied

Contents

The problem is not necessarily the fault of JHipster, b/c it's only seen when bringing in the 'eclipse' plugin. Color substitution in a BufferedImage Do Morpheus and his crew kill potential Ones? In this case, we simply need to add a curly brace to close the main method on the line before where the compiler issued the warning. Java Code: //Mike Ferrara //Lab 2: 8.13 import java.util.*; public class PhoneBookList { public static void main(String[] args) { Scanner keyboard = new Scanner(System.in); String[] nameList = new String[5]; String[] numberList More about the author

The error message for this kind of error is similarly irrelevant toward the end of the message. Im not quite sure what parameters your talking about. Mr.M 32 734 posts since Dec 2012 Community Member More Recommended Articles About Us Contact Us Donate Advertising Vendor Program Terms of Service Newsletter Archive Community Forums Recent Articles © 2002 Forum Program Your Site General Web Development & Application Design Issues cannot be applied to (java.lang.String) The SitePoint Forums have moved. http://stackoverflow.com/questions/5410758/java-lang-string-cannot-be-applied-to-java-lang-object

Java Lang String Cannot Be Applied To Java Lang String

Possible repercussions from assault between coworkers outside the office How do pilots identify the taxi path to the runway? public void run() { String s = ""; // s declared as String Object o = s; // o declared as Object // works because a String is also an Object okay so by leaving out the parameters u mean take away the ()? I did experience the same issue as the original poster.

Win a copy of Cybersecurity Lexicon or Cyber-Physical Attack Recovery Procedures: A Step-by-Step Preparation and Response Guide in the Security forum! Now the problem is with the priority queue, it gives me an "operator < cannot be applied to int, java.lang,string " error msg. Thanks a lot, Brian Henry Wong author Marshal Posts: 21906 87 I like... Operator Cannot Be Applied To Java.lang.object Int how would i get it there...

they are: File: C:\Program Files\Java\New Folder\Bank.java [line: 19] Error: getName(java.lang.String) in Customer cannot be applied to () File: C:\Program Files\Java\New Folder\Driver1.java [line: 6] Error: cannot find symbol symbol : constructor Bank(int) Operator Cannot Be Applied To Java Lang String We recommend upgrading to the latest Safari, Google Chrome, or Firefox. However, there are some applications where you need to do something like a String to int conversion, such as when the String is a representation of a number: public class Test see: http://gradle.org/docs/current/userguide/userguide_single.html#sec:gradle_configuration_properties I though (and tried) to put those properties in the build.gradle (with def var = '') because it felt more "the gradle way" but putting liquibase_hibernate4_version property in gradle.properties

Browse other questions tagged string char charsequence or ask your own question. Cannot Be Applied To Java.lang.string Int Just look at the line, and you should easily see which variable you are trying to use. To acknowledge this, you can use a typecast: public class Test { public static void main(String[] args) { int pi = (int)3.14159; System.out.println("The value of pi is: " + pi); } Still trying everything but nothing, do i need to put something after the method call in the ()?

Operator Cannot Be Applied To Java Lang String

Make Withdrawl"); System.out.println("4. http://www.sitepoint.com/forums/showthread.php?609179-cannot-be-applied-to-(java-lang-String) Why is (a % 256) different than (a & 0xFF)? Java Lang String Cannot Be Applied To Java Lang String Henry Wong author Marshal Posts: 21906 87 I like... Object In Object Cannot Be Applied Exit"; then you can System.out.println(bank.menu()); o ok great thanx it worked Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #14 Brandon222 D.I.C Head Reputation: 0 Posts:

One way to diagnose where the problem is occuring is to use the CTRL-A + TAB shortcut to attempt to properly indent your code. my review here You want the compareTo() method. Why isn't this piece of code creating the array? : Book[] books; Book addBook(Book b) { //Adds books to the array of this library books[numBooks] = b; numBooks++; return b; } Sometimes all you need is a curly brace at the end of your file; other times you may have missed a curly brace or added an extra curly brace in the Java Cannot Be Applied To Int

an... Consider the following program: public class Test public static void main(String[] args) { my_method(); } public static void my_method() { System.out.println("Hello, world!") } } 2 errors found: File: Test.java [line: 1] Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #7 Jayman Student of Life Reputation: 421 Posts: 9,532 Joined: 26-December 05 Re: Error: cannot be applied to click site Now, if I remove the two line, stay ok!

Once the curly braces in the program match up appropriately, the compiler will not complain: public class Test { public static void main(String[] args) { my_method(); } public static void my_method() Java Operator Cannot Be Applied In the gradle.properties file both are set the correct way. Only a compiler can force you to include the empty constructor not Java itself.

How EXACTLY can +=/-= operators be interpreted?

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed i thought those were needed, i need the user to be able to input into that method so it can save it and return it. For example: public class Test { public static void main(String[] args) { int[] arr = {1, 2, 3}; for (int i = 0; i <= arr.length; i++) { System.out.println(arr[i]); } } Exit"; then you can System.out.println(bank.menu()); This post has been edited by pbl: 16 November 2008 - 05:23 PM Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #12

Whatever site that you "looked online", please don't use that site again -- as the explanation is a bunch of gibberish. Now it is telling me that the symbol for Book isn't found. Am i missing any lines anywhere? http://tcsmacs.net/cannot-be/java-lang-object-cannot-be-applied-to-java-lang-string.php The Errors i recieve are: E:\Lab 2\PhoneBookList.java:20: getName() in PhoneBook cannot be applied to (java.lang.String) entry.getName(keyboard.nextLine()); ^ E:\Lab 2\PhoneBookList.java:22: getNumber() in PhoneBook cannot be applied to (java.lang.String) entry.getNumber(keyboard.nextLine()); ^ Any help?

In this example, we invoked the method using a double, then an int, and then a String-- which is the wrong order! Any help would be greatly appreciated. Personal Open source Business Explore Sign up Sign in Pricing Blog Support Search GitHub This repository Watch 455 Star 5,332 Fork 1,169 jhipster/generator-jhipster Code Issues 28 Pull requests 6 Projects java This question has already been answered.

JHipster member jdubois commented Nov 18, 2014 As we don't provide that plugin by default, I don't think this is necessary. Is there still a way to prevent Trump from becoming president? fixed. –dseibert Mar 24 '11 at 3:11 | show 1 more comment Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using You're allowed to do this by acknowledging to the compiler that you know that you're going to lose precision if you do the assignment.

kind regards, Jos The only person who got everything done by Friday was Robinson Crusoe. I am not sure how my variable for addBook is wrong. The simple fix is to remove the lines sourceCompatibility=1.7 targetCompatibility=1.7 from gadle.properties and add them after the apply plugin: eclipse line in the build.gradle file. I am creating a new instance of the book class like my method addBook is supposed to do.

Therefore, simply delete one of the curly braces for the code to compile: public class Test { public static void main(String[] args) { System.out.println("Hello!"); } } expected Errors of the I just began a new project using JHipster and I love what I see so far! Toshiro Hitsuguya Greenhorn Posts: 19 posted 7 years ago I have also tried to change it to firstLibrary.borrowBook(books[1]); and it is telling me a "non-static varible cannot be referenced from a Why isn't this piece of code creating the array? : Maybe you can start with the Sun tutorial on arrays...

Reply With Quote 09-23-2011,11:19 AM #7 JosAH Moderator Join Date Sep 2008 Location Voorschoten, the Netherlands Posts 14,331 Blog Entries7 Rep Power 25 Re: Java Error cannot be applied to (java.lang.String),