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Java Lang String Cannot Be Cast To Ljava Lang Object

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How to prove that authentication system works, and that customer uses the wrong password? Thanks too!You helped me saving a lot of time I guess;) January 25, 2009 7:11 AM Anonymous said... Thanks for the Tip. public void testSearchCountry() throws Exception { driver.get("http://www.wikipedia.org/wiki/Main_Page"); ReadExcelDemo readXls = new ReadExcelDemo(); List dataList = readXls.getData(); String[] test = new String[dataList.size()]; for (int i = 1; i < dataList.size(); i++) { More about the author

String[] kolumnyZawodników = {"Zawodnik", "Bramki", "Niecelne", "Obronione", "Zablokowane", "Ilość rzutów", "Skuteczność rzutowa"}; Vector vectorKolumn = new Vector(); for(int i = 0; i < kolumnyZawodników.length; i++) { vectorKolumn.addElement(kolumnyZawodników[i]); } Vector> vov = How to find second highest or maximum salary of Em... August 26, 2010 11:01 AM Anonymous said... July 25, 2014 4:54 AM Anonymous said...

Java.lang.string Cannot Be Cast To Ljava.lang.object Hibernate

look for all places where you have used cast operator in Java and verify that whether that code is type-safe or not. asked 6 years ago viewed 56669 times active 5 years ago Upcoming Events 2016 Community Moderator Election ends Nov 22 Visit Chat Linked 0 java.lang.ClassCastException: java.lang.String cannot be cast to [Ljava.lang.Object; How to clear all output cells and run all input cells Example for a commutative subring of a non-commutative ring Why are wavelengths shorter than visible light neglected by new telescopes? Thanks for the tip.

I had already busted my mind for more than a half day in finding the fix for the issue, "struts2 ognl exception for the setter method Ljava.lang.String...". That would be a compile error now. –Thilo Sep 23 '10 at 10:27 That's weird. Browse other questions tagged java object combobox or ask your own question. Java.lang.string Cannot Be Cast To Model August 03, 2012 5:05 PM Anonymous said...

Where to take phone interview while at work Why are wavelengths shorter than visible light neglected by new telescopes? Java.lang.string Cannot Be Cast To Bean How to Create and Evaluate XPath Expression in Jav... But I don't see that you've edited your answer... –Ronald Wildenberg Sep 23 '10 at 10:36 @Ronald. http://stackoverflow.com/questions/29231288/classcastexception-java-lang-string-cannot-be-cast-to-ljava-lang-string Post Reply Bookmark Topic Watch Topic New Topic Similar Threads Reg:: HTMLParser Reg.

Any clues? Ljava.lang.object Cannot Be Cast To Class August 31, 2011 10:30 PM Tonky said... If you want to get List of Objects, they use getSelectedObjects() share|improve this answer answered May 14 '14 at 10:32 user902383 4,30232047 add a comment| Your Answer draft saved draft What is Object in Java Programming and OOPS - Exam...

Java.lang.string Cannot Be Cast To Bean

nice tip, helped me to solve the problem October 10, 2008 4:17 AM Anonymous said... https://coderanch.com/t/633683/java/java-lang-ClassCastException-java-lang October 03, 2010 2:54 AM Anonymous said... Java.lang.string Cannot Be Cast To Ljava.lang.object Hibernate current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. Java.lang.string Cannot Be Cast To Class Vector vectorWierszy = new Vector(); for(int j = 0; j < zawodnicyAtaku.length; j++) { vectorWierszy.addElement(new Object[] {zawodnicyAtaku[j], new Integer(0), new Integer(0), new Integer(0), new Integer(0), new Integer(0), new Double(0)}); } vectorWierszy.addElement(new

Related 1181Regular cast vs. my review here Many of advanced Java IDE like Eclipse and Netbeans will give you hyperlink to navigate till culprit line number in Java file. What you can do is: String theString = "whatever"; String[] myStrings = { theString }; share|improve this answer answered Mar 24 '15 at 11:25 GhostCat 20.2k42045 add a comment| up vote How to check if a number is a palindrome or not in... Java.lang.classcastexception: Java.lang.string Cannot Be Cast To

public void coursename(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); Query query= session.createQuery("select a.courseName,a.courseId from Semester e inner join e.course as a"); for (Iterator it = query.iterate(); it.hasNext();) { Object row[] = (Object[]) Fixed. –Mureinik Apr 23 '15 at 6:03 add a comment| Did you find this question interesting? GO OUT AND VOTE more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / http://tcsmacs.net/cannot-be/java-lang-string-cannot-be-cast-to-ljava-lang-object-hibernate.php Which means you can not store Integers on LinkedList of String, from Java 5 it will result in compile time error.

Try this: Object[] obj = (Object[]) map1.keySet().toArray(); for(int i=0; iThanks, that indeed was helpful!

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Thanks a lot again for valuable tip August 06, 2011 3:24 PM Anonymous said... December 28, 2010 6:52 AM pking said... Amazing! navigate to this website thnks for the post December 18, 2010 12:34 PM Girish Wakure said...

public class LoginAttemps extends Setup { public void testSearchCountry() throws Exception { driver.get("http://www.wikipedia.org/wiki/Main_Page"); ReadExcelDemo readXls = new ReadExcelDemo(); List dataList = readXls.getData(); for (int i = 1; i < dataList.size(); i++) How to decline a postdoc interview if there is some possible future collaboration? Ballpark salary equivalent today of "healthcare benefits" in the US? How to reply?

You saved my life ! August 14, 2009 6:11 AM Anonymous said... So the proper generic for this map is . Can a president win the electoral college and lose the popular vote Formula 1 rebus Why do languages require parenthesis around expressions when used with "if" and "while"?